a triangle having a pereter 56units and iys side are 2x ,2x+3and 2x +5 . find the reapective lenghths of the sides of the triangle
Answers
Answered by
2
let the 1st side be 2x
let the 2nd side be 2x+3
let the 3rd side be 2x+5
perimeter = 56
so,
56 = 1st side + 2nd side + 3rd side
56 = 2x + 2x+3 +2x+5
56= 6x + 8
56-8 =6x
48/6 =x
8=x
or x=8
therefore 1st side = 2×8 =16
2nd side = 19
3rd side = 21
let the 2nd side be 2x+3
let the 3rd side be 2x+5
perimeter = 56
so,
56 = 1st side + 2nd side + 3rd side
56 = 2x + 2x+3 +2x+5
56= 6x + 8
56-8 =6x
48/6 =x
8=x
or x=8
therefore 1st side = 2×8 =16
2nd side = 19
3rd side = 21
jude50:
your welcome
Similar questions