Question

A triangle having a perimeter 56 units and its side are 2x,2x+3and 2x+5 .Find the respective length of the sides of the triangle

Answer 1

perimeter of a triangle=sum of its sides

2x+2x+3+2x+5=56

6x+8=56

6x=48

x=8

one side be 2*8=16

other be 2*8+3=19

third side be 2*8+5=21

Answer 2

Answer:

Step-by-step explanation:

Perimeter of triangle = sum of all the sides

=> 56 = 2x+2x+3+2x+5

=> 56 = 6x+8

=> 56-8 = 6x

=> 48 = 6x

=> 48/6 = x

=> 8 = x

2x = 2*8 = 16

2x+3 = 2*8+3 = 16+3 = 19

2x+5 = 2*8+5 = 16+5 = 21