Question

A triangle is formed by the lines whose equations are AB : x + y - 5 = 0, BC : x + 7y - 7 = 0,
and CA : 7x + y + 14 = 0. Find (i) the bisector of the interior angle at B, and (ii) the bisector of
the exterior angle at C.​

Answer 1

Answer:

Answer-

( identity : (a-b)² = a²-2ab +b²)

= {(2x - 5y)}^{2}=(2x−5y)

2

= {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x)

2

−2(2x)(5y)+(5y)

2

= 4 {x}^{2} - 20xy + 25 {y}^{2}=4x

2

−20xy+25y

2