A triangle is placed in a semicircle with a radius of 9yd, as shown below. Find the area of the shaded region. Use the value 3.14 for π, and do not round your answer. Be sure to include the correct unit in your answer.
Answers
Answer:
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Step-by-step explanation:
Considering that the shaded area is the part of the semi circle outside the triangle:
Area of circle= Pi x radius2 (this means radius squared)
Area of triangle= 1/2 x base x height
1/2 (because it is a semi circle) x 3.14 (in replacement of pi as directed by question) x 9squared= 127.17
127.17 - (1/2 x 18 x 9) = 46.17cmsquared
Answer:
The rectangle has length 9 yds and width 4.5 yds because the radius of the semicircle(half circle) is the same as the width of the rectangle.
The area of the rectangle is
=> A=lw
=> A=9×4.5
=>40.5sq yds.
The area of the whole circle is
=> A=Πr^2
=>A=3.14×4.5^2
=>A=3.14×20.25
=>A=63.585sq yds
The area of the semicircle is 63.585/2=31.7925 sq yds
The area of the region outside the semicircle is the area of the rectangle minus the area of the semicircle.
=>A=40.5-31.7925
=>8.7075 sq yds