A triangle of area 9y cm^2 has beendrawn such that its area is equal to the area of an equilateral triangle of side 6 cm find the value of y.
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Step-by-step explanation:
Area of the given triangle = 9y cm2-----1
Area of equilateral triangle = 6^2×(3^1/2)÷4=9 (3^1/2)--------2
According to qn
9 (3^1/2) = 9*y cm2
y=(3)^1/2
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