a triangle pqr is right angled at q. s is a point on pr such that qs ⊥pr. prove that ∠rqs=qpr.
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Answer:
Step-by-step explanation:
QP=8cm,PR=6cm and SR=3cm
(I) In △PQR and △SPR
∠PRQ=∠SRP (Common angle)
∠QPR=∠PSR (Given that)
∠PQR=∠PSR (Properties of triangle )
∴△PQR∼△SPR (By AAA)
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