a triangle PQR with right angle at Q the value of ,p is PQ=7cm andQR=24cm then find sinx and tan x
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Answered by
1
Answer:
sinR= 7/25 ,tanR =7/24
Step-by-step explanation:
Sinr=opposite/hypotyneuse
PQ²+QR²=PR²
7²+24²=PR²
49+576=PR²
625=PR²
√625=PR
25=PR
TanR =opposite/adjacent=7/24
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