Question

A triangle shaped land has the sides in the ratio 3:5:7, if its perimeter is 300 meter. ​

Answer 1

Answer:

Step-by-step explanation:

$The \:sides \;of \:a \:the \:triangular \:plot \:are \: in \:the \:ratio \:of \:3:5:7 \: let \:the\\sides \:of \:the \:triangle\:be\:3x,\:5x\:and\:7x$

Also it is given that the perimeter of the triangle is 300 m therefore,

$3x+5x+7x=300\\15x=300\\x=20$

Therefore, the sides of the triangle are 60,100 and 140.

$S=60+100+140/2\\\\=300/3\\\\=150 \:m$

Area of the triangle is:

$A=\sqrt s(s-a)(s-b)(s-c)\\\\=\sqrt 150(150-60)(150-100)(150-140)\\\\=\sqrt 150*90*50*10\\\\\sqrt 6750000\\\\1500 \sqrt 3\:m^2$

Hope it helps you

Answer 2

Answer:

Answer:

Step-by-step explanation:

\begin{gathered}The \:sides \;of \:a \:the \:triangular \:plot \:are \: in \:the \:ratio \:of \:3:5:7 \: let \:the\\sides \:of \:the \:triangle\:be\:3x,\:5x\:and\:7x\end{gathered}

Thesidesofathetriangularplotareintheratioof3:5:7letthe

sidesofthetrianglebe3x,5xand7x

Also it is given that the perimeter of the triangle is 300 m therefore,

\begin{gathered}3x+5x+7x=300\\15x=300\\x=20\end{gathered}

3x+5x+7x=300

15x=300

x=20

Therefore, the sides of the triangle are 60,100 and 140.

\begin{gathered}S=60+100+140/2\\\\=300/3\\\\=150 \:m\\\end{gathered}

S=60+100+140/2

=300/3

=150m

Area of the triangle is:

\begin{gathered}A=\sqrt s(s-a)(s-b)(s-c)\\\\=\sqrt 150(150-60)(150-100)(150-140)\\\\=\sqrt 150*90*50*10\\\\\sqrt 6750000\\\\1500 \sqrt 3\:m^2\end{gathered}

A=

s

(s−a)(s−b)(s−c)

=

1

50(150−60)(150−100)(150−140)

=

1

50∗90∗50∗10

6

750000

1500

3

m

2

Hope it helps you