Question

A triangle with side lengths 'a' inches, 'b' inches, and 'c' inches has a perimeter of 25 inches. If side a is twice that of side b, and side b is half of side c, what is the length of side b?

Answer 1

let c be 'x' inches

b = ½x

a=2×½x

ATP,

X+½X+X=25

5X/2=25

5X=25×2

X=50/5

X=10

Therefore, length of b is ½of x=½×10=5inch