Math, asked by aravind70342, 1 year ago

a triangle with sides lengths in the ratio 3:4:5 inscribed in radius 3 what is area of triangle

Answers

Answered by bhalaraneha
0
here, triangle is a right triangle [ 3-4-5 is a pythagorean triple]
take a side langhts of triange as 3x, 4x , 5x 

circle raidius is 6 and so..
5x = r
 x =  6 
        5
so area of the triangle is=  1 * 3x * 4x
                                       2  
                                    = 1 *
 18 * 24 
                                       2     5    5
                                    = 216
                                        25
                                    = 8.64
 

Answered by varadagovind
0

Answer:

Step-by-step explanation:

sum of angles of triangle is 180 degree

Triangle with sides in the ratio is 3:4:5

3x+4x+5x=189

12x=180

x=180/12

x=15

3x =3×15=45degrees

4x=4×15=60degrees

5x=5×15=75 degree

let ABC be triangle

AB =15cm

BC=60cm

CA=75cm

BC be base of triangle

AB be height

area of triangle =1/2×base×height

=1/2×60×15

=450cm

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