Question

A triangular block of mass M rests on a smooth surface as shown in figure. A cubical block of mass m rests on the inclined surface. If all surfaces are
frictionless, the force that must be applied to M along horizontal direction so as to
keep m stationary relative to M is :​

Answer 1

Answer:

The answer is F = (M +m)gtanθ

Explanation:

In this case, M and m are moving with the same acceleration "a". Note that a is along horizontal i.e. x-direction only.

For M and m :

F - N2Sinθ = ma .....(1)

mg - N2Cosθ = 0  

=> N2 = mg/Cosθ   ......(2)

N2 Sinθ = ma ...(3)

From equation (2) and (3) we can say that

a = gtanθ

By substituting equation (3) into (1) we obtain.

F = (M +m)a

F = (M +m)gtanθ

Thus the force that must be applied to M along horizontal direction is F = (M +m)gtanθ .

Answer 2

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