Question

A triangular field has sides which are in ratio 9: 10: 11 and an area of 270√2cm² find the sides of the triangle. Amswer the question with all the steps required.​

Answer 1

⇒Let x be common ratio

∴ Sides of triangle will be: 12x,17x and 25x

⇒Perimeter =540 cm(given)

⇒12x+17x+25x=540 cm,

⇒54x=540 cm

⇒x=10 cm

∴ Sides of triangle: a=120,b=170,c=250 cms

⇒2S=540

⇒S=270 cm

A=

s(s−a)(s−b)(s−c)

=

270(270−120)(270−170)(270−250)

cm

2

=

270×150×100×20

cm

2

A=9000 cm

2

Answer 2

Answer:

⇒Let x be common ratio

∴ Sides of triangle will be: 12x,17x and 25x

⇒Perimeter =540 cm(given)

⇒12x+17x+25x=540 cm,

⇒54x=540 cm

⇒x=10 cm

∴ Sides of triangle: a=120,b=170,c=250 cms

⇒2S=540

⇒S=270 cm

A= s(s−a)(s−b)(s−c)

=270(270−120)(270−170)(270−250)

=2cm

270×150×100×20

2cm

A=9000

2cm