Question

- A triangular field has the measures 320 m. 240 m
field.
and 400 m. Find the area
the
area of the field.​

Answer 1

Answer:

38400 sq.m

Step-by-step explanation:

side of field are 320m,240m,400m respectivelynow by heron's formula

$\sqrt{s(s - a)(s - b)(s - c)$

&

$s = (a + b + c )\div 2$

s=(320+240+400)÷2

s=960÷2

s=480

now put s and a b c in formula

we get

$\sqrt{480} (480 - 320)(480 - 240)(480 - 400)$

by solving this sqrt we get 38400sq. m of area

Answer 2

Answer:

• Given the dimensions of the triangular field which is 320 m,240mand 400 m

From the above dimensions we concluded that it's a scalen triangle so the area if a scalen triangle can be calculated out by using the herons formula which is as follows

$area \: of \: scalen \: triangle = \sqrt{s(s - a)(s - b)(s - c)}$

Where S is called semiperimeter And a,b,c are the sides of the triangle

Let, us first find the semiperimeter of the triangle this is as follows

$= > s = \frac{sum \: of \: sides}{2} \\ \\ = >s = \frac{320 + 240 + 400}{2} \\ \\ = > s = \frac{960}{2} \\ \\ = > s = 480$

So the area is

$= > area = \sqrt{480(480 - 320)(480 - 240)(480 - 400)} \\ \\ = > area = \sqrt{480 \times 160 \times 240 \times 80}$

[tex] = > area = 38400 m²

So from the above calculation we concluded that the area if the triangle is 38400 m²