Question

A triangular field of side 20m each, has a cow tied at each of its three corners. If the length of each rope is 7m. Find the area in which the three cows can graze.

Answer 1

Answer:

it is an equilateral triangle

=the area of triangle-3×π×r×r

you can get the answer

Answer 2

The area in which the three cows can graze = 77 m².

The three cows are tied at the three corners of an equilateral triangle of side 20 m.

The cows are tied to a rope of 7 m , which will act as the radius (r) of a sector and the angle of the sector (X) is equal to 60°.

Area of the sector = (X/360) × πr²

= (1/6) × (22/7) × 49

= 77/3 m²

The total area of the triangular field grazed by the three cows = 3 × (77/3)

= 77 m²