A triangular field whose sides are 60m,111m,153m
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Answer:
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Step-by-step explanation:
S=(60+153+111)/2
S=324/2
S=162
A=√([S][S-A][S-B][S-C])
A=√([162][162-60][162-153][162-111])
A=√([162][102][9][51])
A=√7,584,516
A=2,754 sq cm
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