Question

A triangular garden has two equal sides
and the length of one of its side is 50
metres. Find the length of the two
equal sides, if the cost of paving the
garden is Rs 3500 at Rs 2.50 per
square metre.
(a) 63.11 m (b) 61.33 m
(C) 64.39 m (d) 65.33 m​

Answer 1

Answer:

b) a= 61.33 m

Step-by-step explanation:

Area of the triangular garden = total cost of pavement/cost per square meter

= 3500/2.50 = 1400 m^2

one of the side of the Δ = 50 m

now it is given that the Δ is isosceles

area of an isosceles Δ = $\frac{1}{2} \sqrt{a^2-\frac{b}{2}^2 }\times b$

where a=  length of equal side and b= 50 m

putting values we get

1400 = $\frac{1}{2} \sqrt{a^2-\frac{50}{2}^2 }\times 50$

solving the above equation we get

a= 61.33 m

hence the length of the two

equal sides a= a= 61.33 m hence option b is correct.