Question

A triangular glass prism with apex angle 60 degree

Answer 1

Answer:

Given data:

Apex angle,

A

=

60

∘

Refractive index of the triangular prism,

μ

=

1.50

Angle of the incident,

i

=

45.6

∘

We know that,

i

+

i

′

=

A

+

σ

Here,

i

′

and

σ

are the angle of emergence and angle of the deviation.

Thus,

σ

=

i

+

i

′

−

A

−

−

(

1

)

From Snell's law,

μ

=

s

i

n

i

s

i

n

i

′

Plugging in values,

1.50

=

s

i

n

45.6

s

i

n

i

′

On solving for

i

′

,

i

′

=

28.45

∘

From (1),

σ

=

45.6

+

28.45

−

60

=

14.05

∘

.

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Answer 2

Answer:

Step-by-step explanation:

A triangular glass prism with apex angle 60.0 degrees has an index of refraction of 1.50. Find the angle of deviation if the angle of incidence on the first surface is 45.6 degrees?

Angle through Prism:

Assume there is a glass prism having an angle of prism  

A

and the angle of incidence and the emergence for a light ray are  

i

and  

i

′

, respectively. In this case, the angle of deviation can be given as,

δ

=

i

+

i

′

−

A

.

Answer and Explanation:

Given data:

Apex angle,  

A

=

60

∘

Refractive index of the triangular prism,  

μ

=

1.50

Angle of the incident,  

i

=

45.6

∘

We know that,

i

+

i

′

=

A

+

σ

Here,

i

′

and  

σ

are the angle of emergence and angle of the deviation.

Thus,

=

14.05

∘

.