Question

A TRIANGULAR HAS A PERIMETER OF 50 UNITS. IF TWO OF ITS SIDES ARE EQUAL,AND THE THIRD SIDE IS 5 MORE THAN THE EQUAL SIDE,WHAT IS THE LENGTH OF THE THIRD SIDE?

Answer 1

Step-by-step explanation:

Let

x

= the length of two of the sides (the ones that are equal)

Let

x

+

5

= the length of the third side

x

+

x

+

x

+

5

=

50

add up all three sides

3

x

+

5

=

50

combine

3

x

=

45

subtract 5 from both sides

x

=

15

divide by 3

The length of the third side =

x

+

5

= 20.

it is long but it is helpful