Question

A triangular has sides 9 cm, 12 cm and 15 cm. Find the length of perpendicular from the opposite vertese to the side whose length is 15 cm​

Answer 1

Step-by-step explanation:

Here,

a=5,b=12,c=13

s=

2

1

(a+b+c)=15

Area of the triangle, A =

s(s−a)(s−b)(s−c)

A=

15(15−5)(15−12)(15−13)

A=30 cm

2

Let p be the length of perpendicular. Then,

A=

2

1

×13×p

Therefore,

2

1

×13×p=30

p=

13

60

cm

Answer 2

Step-by-step explanation:

It is clear that the triangle is a right angled triangle.

Let AB=12 cm BC=5 cm and AC=13 cm

Now a perpendicular is drawn from A to AC.

ar(ABC)=1/2 AB.BC=1/2CA.BD.

BD=AB.BC/CA

Putting the respective values of the sides we get,

BD=60/13 cm