A triangular park ABC has sides 120m ,80m , 50m
Answers
here, a=120m,
here, a=120m,b=80m,
here, a=120m,b=80m,c=50m
here, a=120m,b=80m,c=50mand, s=
here, a=120m,b=80m,c=50mand, s= 2
here, a=120m,b=80m,c=50mand, s= 2a+b+c
here, a=120m,b=80m,c=50mand, s= 2a+b+c =
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass =
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass = s(s−a)(s−b)(s−c)
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass = s(s−a)(s−b)(s−c) =
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass = s(s−a)(s−b)(s−c) = 125(125−120)(125−80)(125−50)
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass = s(s−a)(s−b)(s−c) = 125(125−120)(125−80)(125−50) =375
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass = s(s−a)(s−b)(s−c) = 125(125−120)(125−80)(125−50) =375 15
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass = s(s−a)(s−b)(s−c) = 125(125−120)(125−80)(125−50) =375 15 m
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass = s(s−a)(s−b)(s−c) = 125(125−120)(125−80)(125−50) =375 15 m 2
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass = s(s−a)(s−b)(s−c) = 125(125−120)(125−80)(125−50) =375 15 m 2 cost of fencing =[(a+b+c)−3].20
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass = s(s−a)(s−b)(s−c) = 125(125−120)(125−80)(125−50) =375 15 m 2 cost of fencing =[(a+b+c)−3].20=[250−3].20
here, a=120m,b=80m,c=50mand, s= 2a+b+c = 2250 =125Area she need to plant grass = s(s−a)(s−b)(s−c) = 125(125−120)(125−80)(125−50) =375 15 m 2 cost of fencing =[(a+b+c)−3].20=[250−3].20=Rs4940
Answer: