Math, asked by routraymanoranjan85, 7 months ago

A triangular park ABC has sides 120m, 80m and 50m. A gardener Dhania has to put a fence around it and also plant grass inside. How much area does she need to plant ? Find the cost of fencing it with barded wire at the rate of rupees 20 per m leaving a space 3m wide for a gate on one side .​

Answers

Answered by sowmyau1979
0

Answer:

triangular park ABC has sides 120m, 80m and 50m. A gardener Dhania has to put a fence all around it and also plant grass inside. How much area does she need to plant? Find the cost of fencing it with barbed wire at the rate of Rs 20 per metre leaving a space 3m wide for a gate on one si.

Step-by-step explanation:

Answered by neerajantony
0

Answer: area she needs to plant is 375√15m2

              perimeter: 247 m

Step-by-step explanation:

area:

heron's formulae: √s(s-a)(s-b)(s-c)

s=(a+b+c)/2=(120+80+50)/2=250/2=125

=>√125(125-120)(125-80)(125-50)

=>√125x5x45x75=√2109375 =  375√15m2

perimeter: (the question had asked to leave 3 meters)

120+80+50-3=247meters

cost of fencing per meter: 20rupees

so 247 x 20 = 4940

Hope it has answered your question :)

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