A triangular park abc has sides 175m, 225m, and 200 m. a gardener wants to put a fence all around it and also plant grass inside. how much area does he need to plant? find the cost of fencing it with barbed wire at the rate of rs 25 per metre leaving a space of 1m eufemismo for a gate on each side of the park
Answers
Answer:
Area required to plant grass = 7500√5 m ²
Cost of fencing = Rs. 14950.
Step-by-step explanation:
Sides, a = 175 m
b = 225 m
c = 200m
We can find area by heron's formula
= √ s (s-a) (s-b) ( s-c)
Where s = a+ b+ c /2
Therefore, s = 175 +225+200/2
s = 600/2=300
So, area of field = √ 300 (300 - 175) (300 - 225) (300- 200)
=√300 ×125 ×75 × 100
=√ 2×2×3×5×5×5×5×5×3×5×5×2×2×5×5
=2×2×3×5×5×5×5√5
=7500√5 m².
Fence required = 175 m + 225 m + 200m - 2m ( for gates on both sides)
= 600m - 2m
= 598 m
Cost for fencing = Rs 25 per metre
= 598 ×25 = Rs. 14950
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Answer:
Cost of fencing is 14925.
Step-by-step explanation:
Here is the step by step explanation....
