Question

A triangular park ABC has sides 40 m, 32 m and 24 m. Inside it a triangular part ADC is reserved for parking and food stalls. In the remaining part ABCD grass is to be
grown. Find the area of grass portion (shaded region) and also find the cost of fencing it with barbed wired at the rate of Rs.20 per m leaving a length of 3m wide for the gate

Answer 1

Answer:

Let the sides of ∆ ABC be a= 40m, b = 32cm, 24m

To find area we must use Heron's formula because we are not given the height.

Using Heron's formula, we get:-

semi perimeter = a+b+c/2

=40+32+24/2

= 48m

s-a=48-40=8m

s-b= 48-32= 16m

s-c= 48-24= 24m

Area of ∆ ABC= √s(s-a)(s-b)(s-c)

= √48×8×16×24

= 384 m^2

Therefore,

Area of the triangle is 384 m^2