Question

A triangular park has sides 100m, 100m and 160m. A gardener has to put a fence all around it    and also plant grass inside. Find the cost of fencing it with barbed wire at the rate of rupees 10 per meter leaving a space 2m wide for a gate on one side and how much area does he need to plant?​

Answer 1

Step-by-step explanation:

here, a=100m

b=100m

c=160m

and s = a+b+c/2 = 100+100+160/2 = 360/2=180

s=180

area = √ s(s−a)(s−b)(s−c)

= √ 180(180-100)(180-100)(180-160)

= √ 180(80)(80)(20)

= √ 4800 m²

cost of fencing = [(a+b+c)-2]×10

= [(100+100+160)-2]×10

= [360-2]10

= [ 358]10

= 3580 rupees

Answer 2

So, the gardener needs to plant an area of 4800m^2.