Question

A triangular park has sides 120 m, 80 m and 50 m. A gardener has to put a fence a! around
it and also plant grass Inside . How much area does he need to plant ? Find the cost of
Fencing it with barbed wire at the rate of Rs. 20 per metre leaving space 3 m wide for a gate​

Answer 1

Area = I452.37m2

fencing=Rs.74l

Answer 2

Answer:

it is simple

side A = 120m

side B = 80m

side C = 50m

semi perimeter = (120 +80+50)÷2 =125

Area of tri angular field =

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{125(125 - 120)(125 - 80)(125 - 50)}$

$\sqrt{125 \times 5 \times 45 \times 75}$

$\sqrt{2109375} = 1452.36$

area required for planting = 1452.36 m

total area for fencing = 125 m(we have already find the semiperimeter of feild above so now we can find perimeter = 250m )

For 122 m = 247× 20 = 4940 rupee