Math, asked by daiwik12, 8 months ago

A triangular park has sides 120 m, 80 m and 50 m. A gardener has to put a fence all
around it and also plant grass inside. How much area does he need to plant?
Find the cost of fencing it with barbed wire at the rate of Rs. 20 per metre, leaving a space of 3 m wide for a gate on Find the area of the plot.

Explain it with steps or I will not make you the BRAINLIEST

Answers

Answered by vikhyat04

Perimeter of the garden=120+80+50 =250m As space of 3 m wide for a gate is left on one side, so the length of wire required=(250-3)=247m. Cost of fencing=247X20=Rs 4940. semiperimeter(s)=perimeter/2 =250/2=>125m Area of triangle is given by A=sqrt(s(s-a)(s-b)(s-c))=sqrt(125x5x45x75)=(25x15sqrt(15)) => 375 sqrt(15) sq.m

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