Question

a triangular park has sides 120 m , 80m and 50m a gardener has to put a fence all round it with barbed wire at the rate of rs 20 per meter leaving a space of 3 m wide for a gate on one side
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Answer 1

here, a=120m,

b=80m,

c=50m

and, s=

2

a+b+c

=

2

250

=125

Area she need to plant grass =

s(s−a)(s−b)(s−c)

=

125(125−120)(125−80)(125−50)

=375

15

m

2

cost of fencing =[(a+b+c)−3].20

=[250−3].20

=Rs4940