Question

a triangular park has sides 120m, 80m,50m.A gardener has to put a fence all around it and also plant grass inside. how much area does he need to plant? find the cost of fencing it with barbed wire at the rate of rs 20 per metre, leaving a space of 3mwide for a gate on one side​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

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♡ ↪ Perimeter:

50 + 80 + 120 = 250m

50+80+120

=250m

Then,

Semiperimeter {250}{2} = 125m}

2

250

=125m

• s - a ( 125-120 ) = 5ms−a(125−120)=5m

• s - a ( 125-80 ) = 45ms−a(125−80)=45m

• s - a ( 125-50 ) = 75ms−a(125−50)=75m

Area = sqrt{125(5)(45)(75)} = 375 sqrt{{15}m^{2}

Area= 125(5)(45)(75)

=375

15m

2

perimeter = 250 - 3m = 247m

Now,perimeter=250−3m

=247m

Cost = 20 times 247Cost=20×247

♡

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