Math, asked by Nishantanchan1548, 8 months ago

A TRIANGULAR PARK HAS SIDES 52M 56M AND 60M .FIND THE COST OF PLANTING GRASS IN THE PARK AT THE RATE OF RUPEES 5 PER METER SQUARE .OF A SPACE OF 4M IS TO BE LEFT FOR THE ENTRY GAP FIND THE COST OF FENCING THE PARK AT THE RATE OF RUPEES 18 PER METER

Answers

Answered by aquibkhanmaaq211
4

Answer:

Dimensions of triangular park are as

52,56,60 meters

Calculating area by herons formula

√s(s-a)(s-b)(s-c),where s is semi perimeter

now, s=(a+b+c)/2

s=(52+56+60)/2

s=168/2

s=84m

now,

Area=✓s(s-a)(s-b)(s-c)

✓84(84-52)(84-56)(84-60)

✓84×32×28×24

197087.415 m²

cost of planting grass @5 m² leaving area of 4m²

(197087.4-4)×5

197083.4×5

Rs 985417.075

cost of fencing @18 per m

perimeter = (52+56+60)

=108 m

fencing cost= (108×18)

Rs1944

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