Question

a triangular part enclosed on two sides by a fence and the third side by a Straight riverbank the two side having fence are of same length X the maximum area enclosed by the park is

Answer 1

$<b>$AT =x sin α

BT = x Cos α

Area of triangle =( 1/2 × base × height) sq.unit

= 1/2 ×( 2BT) × (AT)

=1/2 ( 2x² Cos α sin α)

= 1/2 x² sin 2 α ≤ 1/2 x² as -1 ≤ sin 2 α ≤ 1

Maximum area of triangle ABC = 1/2 x²

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