Question

A triangular wire who is perimeter is 27 cm is bent into a circle. Find the diameter of the circle​

Answer 1

Answer:

The perimeter of triangle=circumference of circle

27=2πr

27=2*3.14*r

27/2*3.14=r

4.3=r

R*2=diameter

8.6 cm=diameter

Step-by-step explanation:

Answer 2

Answer:

8.5909 cm

Step-by-step explanation:

Since the length of the wire will be same after bending it into a circle, the perimeter of the circle will also be 27cm.

Perimeter of circle= 2πr (We take π=22/7 until given)

So, 27= 2×(22÷7)×r

27÷2= 22÷7×r

(27÷2)×(7÷22)= r

r=4.295454...

since diameter= 2r

So d= 8.590909...