a tricky question.
Please ope. And see question is their
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in triangle ABC
ACD=cab+ABC. exterior angles
130=2cab
cab=65=abd
now
ACB=180-130=50
now ACd=ebc =n+ABC=n+65
130=n+65
n=65
ACD=cab+ABC. exterior angles
130=2cab
cab=65=abd
now
ACB=180-130=50
now ACd=ebc =n+ABC=n+65
130=n+65
n=65
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