Question

A tricycle weighing 200 N has a small wheel symmetrically placed 500 mm in frontof two large wheels which are placed 400 mm apart. If centre of gravity of thecycle be at a horizontal distance of 150 mm from the rear wheels and that of the rider,whose weight is 150 N, be 100 mm from the rear wheels, find the thrust on the groundunder the different wheels

Answer 1

Answer:

225

Explanation:

In the given figure, the tricycle with two front wheels A and B with one rear wheel C with center of gravity of machine G1 and that of rider G2.

Now, force at G1=20×10=200N

Force at G2=400 N

Let FC = Force on ground under rear wheel C

Force at D = FD=2FA acts on mid-point of AB.

Taking torque about D, for equilibrium,

Fc×100=200×25+400×10=9000

∴ Thrust on each front wheel is N.

∴ 2N + F_(c)=Totalweight=600NthereforeN=

600-FC

2

 

= 255 N