Question

A tricycle weighing 200 N has a small wheel symmetrically placed 500 mm in front of two large wheels which are placed 400 mm apart. If centre of gravity of the cycle be at a horizontal distance of 150 mm from the rear wheels and that of the rider, whose weight is 150 N, be 100 mm from the rear wheels, find the thrust on the ground under the different wheels.

Answer 1

Answer:

Atricycle 200 n has a small wheel symmetrically placed 500 mm in front

of two large wheels are placed 400 mm apart. if centre of gravity of the

cycle be at a horizontal distance of 150 mm from the rear wheels and that of the rider,

whose weight is 150 n, be 100 mm from the rear wheels, find the thrust on the ground

under the different wheels.

Answer 2

Given:

1. Weight of tricycle = 200N
2. Distance between front wheel and rear wheels = 500 mm
3. Distance between two rear wheels = 400 mm
4. Distance of centre of gravity of the cycle from the rear wheels = 150 mm
5. Weight of rider = 150N
6. Distance of from the rear wheels = 100 mm

To find:

1. The thrust on the ground under the different wheels

Answer:

• Let, the tricycle's with two front wheels be identified by A and B with the rear wheel with C
• Let, the center of gravity of tricycle be G1 and that of rider G2
• The, force at G1 = 20×10 = 200N
• Force at G2 = 400N
• Let FC = Force on ground under rear wheel C
• Force at D = FD = 2 FA acts on mid-point of AB.
• Taking torque about D, for equilibrium,
• Fc×100 = 200×25 + 400×10 = 9000N
• ∴Thrust on each front wheel is N.
• ∴2N + F_(c)=Totalweight=600N
• Therefore N =600− FC2N = 600 - FC2 = 255 N

Thus thrust on the ground = 255 N