A trihybrid cross is made between two yeast, both with genotype A/a, B/b, C/c. What proportion of the offspring will be of genotype a/a, b/b, c/c?
a. 1/8 b. 1/32 C. 1/64 d. 1/74
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Answer:
there1
Explanation:
If we consider a cross between AaBbCc, the value of n = 3.
The maximum number of possible gametes is 2 raised to 'n'.
Value of n = 3.
Thus, maximum 2x2x2 = 8 gametes are produced. This makes it clear that maximum offspring produced is 8x8 = 64. The possibility of a recessive genotype in this combination of Punnet square is 1/64. This means that one out of 64 offspring produced will have aabbcc genotype.
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