A trivalent metal oxide contains 68.4% of oxygen. what is the atomic mass of the metal
Answers
Answered by
8
Answer:
Assume, At. Mass of Metal be ‘M’ and Oxygen be ‘O’
then,
Molecular Mass of metal oxide = 2 * M + 3 * O = 2M + 48
According to question,
68.4 %of mass of Metal Oxide is equal to Mass of Oxygen in it
68.4 %
of (2M + 48) = 48
or, 2M + 48 = 48* (100/68.4)
or, 2M = (4000/57) - 48
or, M = 1264/(57*2) = 11.08
therfore by solving you get, Atomic Mass of the Metal as 11.08 amu
Step-by-step explanation:
Similar questions