Math, asked by destructorgamer397, 3 months ago

A trollery can carry 240kg of fertiliser at a time.If it is necessary to spread 50kg of fertilisers fer hecterhow many trips of the trolley are necessary to fertilise a 12km by 450m large crop field​

Answers

Answered by aaronpv930
1

Answer:

Step-by-step explanation:

Area of crop field = 1.2 Km by 450 m

                             = 1200 m × 450 m→→[1 Km = 1000 m]

                              = 5,40,000 m²

As, 1 Hectare = 10,000 m²

Area of crop field == 54 hectare

Amount of fertilizer that a trolley can carry = 240 Kg

Amount of fertilizer required  in a crop field = 50 Kg per Hectare

Total amount of fertilizer required in the crop field whose area is 54 hectare =54 × 50 Kg=2700 Kg

Number of Trollies of fertilizer required if the total amount of fertilizer required in the crop field is 2700 Kg and a single trolley can carry 240 Kg of fertilizer=  

The number of trollies must be an integral value. It can't be equal to 11.25. So minimum number of trollies must be equal to 12 Trollies.  

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