Question

a trolley can carry 240 kg of fertiliser at a time .if it is necessary to spread 50 kg of fertiliser per hectare ,how many trips of trolley are necessary to fertiliser a 1.2 km by 450 m large crop field?

Answer 1

Solution:

Area of crop field = 1.2 Km by 450 m

                              = 1200 m × 450 m→→[1 Km = 1000 m]

                               = 5,40,000 m²

As, 1 Hectare = 10,000 m²

Area of crop field =$\frac{5,40,000}{10,000}$= 54 hectare

Amount of fertilizer that a trolley can carry = 240 Kg

Amount of fertilizer required  in a crop field = 50 Kg per Hectare

Total amount of fertilizer required in the crop field whose area is 54 hectare =54 × 50 Kg=2700 Kg

Number of Trollies of fertilizer required if the total amount of fertilizer required in the crop field is 2700 Kg and a single trolley can carry 240 Kg of fertilizer=  $\frac{2700}{240}=11.25$

The number of trollies must be an integral value. It can't be equal to 11.25. So minimum number of trollies must be equal to 12 Trollies.  

Answer 2

Answer:

answer is 11 1/4 trips or 12 trips

Step-by-step explanation:

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