A trolley goin down an inclined plane , has an acceleration of 2cm-2 . what will be its velocity 3s after the start?
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Answered by
0
Answer:
we can do this problem with the first equation of motion.
Explanation:
v=u+at
here,a=2cm^-2,initial velocity =0 as it starts from rest,time=3s.
substituting the values in the equation, we get..
v=0+2*3
v=0+6
v=6cm/s.
Hope it helps..
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Answered by
1
Explanation:
v=u+at
v=0+0.02*3
v=0.06m/s
or
v=6cm/s
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