Question

A trolley is being pulled up an incline plane by a man sitting on it he applies a force of 250 Newton if the combine mass of the man in the trolley is 100 kg the acceleration of the trolley will be the Angle of incline is 15 degree

Answer 1

Force applied by the man on rope will be given by F = 250 N

now net force applied by tension force on the trolley system

$F_{net} = 3T = 3*250 = 750 N$

now total weight along the inclined plane downwards

$W = mgsin\theta$

$W = 100* 9.8* sin15 = 253.6N$

now the net upward force along the inclined)

$F_{net} = 3T - W = 750 - 253.6 = 496.35$

now by Newton's 2nd law

$F_{net} = ma$

$496.35 = 100 *a$

$a = 4.96m/s^2$

so the acceleration of the trolley and man system will be 4.96 m/s^2 along the inclined plane.

Answer 2

Answer:

Explanation:

The soln is given is sufficient

l am providing u a exact question with diagraamm

I hope u understand