Question

A trolley moves down a slope from rest with
constant acceleration. In the first second of its
motion it travels 1.6 m. Its acceleration (in m/s2) is
177 3.2
(2) 1.6
(3) 0.8
(4) 2.4​

Answer 1

Answer:

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Step-by-step explanation:

s = ut + (1/2)at²

1.6 = 0.5a(1)²

3.2 = a

Answer 2

★Given That:-

⇒u = 0

⇒t= 1

⇒s = 1.6m

Here u is initial velocity, t is time taken, s is distance travelled

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★SOLUTION:-

⇒s = ut² + ½ × at².

⇒s = ½ ×at²

$\frac{1.6 \times 2}{1} = a \\ \\ \huge\boxed{a = 3.2}$

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I HOPE IT HELPS.