Question

A trolley of mass 200 kg moves on a level track for a distance of 500

metres. If the resistance of the track is 100 N, find the work done in

moving the trolley
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Answer 1

Answer:

Explanation:

a force must be applied to the trolley to overcome frictional force

by boundary conditions a minimum of 100 N is required

hence work = force x displacement

                    = 100 x 500 = 50 kJ

Answer 2

Answer:

The work done in the moving trolley is $\bold{93\times 10^4}$

Explanation:

Given that

Mass of the trolley $=200kg$

Distance$=500 metres$

resistance of track$=100N$

Now we know that $W=(F-F_{res})S$

By substituting all the values, we have

$W=(200\times9.8-100) 500\\W=(2\times 980-100) 500\\W= (1960-100)500\\W=1860\times 500$

Further solving, we get

$W=930000 or 93\times10^4$

Hence, The work done in the moving trolley is $\bold{93\times 10^4}$