A trolley of mass 20kg was orginally at test on a smooth horizontal surface. By how much will it accelerate if a pulling force of 22N is applied on it horizontally
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Answer:
Correct option is C)
Here the limiting friction force =μmg=0.25×2×10=5N
Thus the applied force is less than the friction force. So there will not have relative motion in between trolley and mass.
therefore, 2=(20+2)a⇒a=0.09m/s
2
The friction force between mass and surface of trolley =20a=20×0.09=1.8N
Explanation:
Correct option is C)
Here the limiting friction force =μmg=0.25×2×10=5N
Thus the applied force is less than the friction force. So there will not have relative motion in between trolley and mass.
therefore, 2=(20+2)a⇒a=0.09m/s
2
The friction force between mass and surface of trolley =20a=20×0.09=1.8N
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