A trolley of mass 300 kg carrying a sandbag of 25 kg is moving uniformly with a speed of 27 km/h on a frictionless track. After a while, sand starts leaking out of a hole on the floor of the trolley at the rate of 0.05 kg s-1. What is the speed of the trolley after the entire sand bag is empty?
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Since the hole is on the floor , that means sand is falling vertically with respect to trolley. Therefore there is no force in horizontal direction hence in horizontal direction momentum is conserved.
Let M= mass of trolley
m= mass of sandbag
v
1
= initial velocity
v
2
= final velocity ( to be found)
Then P
1
=(M+m)v
1
when the sand bag is empty the momentum is
P
2
=(M+0)v
2
Momentum is conserved in horizontal direction so
P
1
=P
2
⇒=v
2
=
M
(M+m)
v
1
=
300
300+25
×27×
18
5
=8.215m/s
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