Question

A trolley of mass 8 kg is standing on frictionless surface inside which an object of mass 2 kg is suspended. A constant force F starts acting on the trolley as a result of which the string 2kg stood at an angle of 37° from the vertical (bob at rest relative to
trolley) Then :
(A) acceleration of the trolley is 40/3 m/sec2. (B) force applied is 60 N
(C) force applied is 75 N.
(D) tension in the string is 25 N​

Answer 1

Answer:

c and d

Explanation:

C and D are asnswers

Answer 2

Answer:

The tension in the string is 25 N and force applied is 75 N.

(C) and (D) is correct option.

Explanation:

Given that,

Mass of trolley = 8 kg

Mass of object = 2 kg

Angle = 37°

We need to calculate the tension

Using equations

$T\sin37=ma$....(I)

$T\cos37=mg$...(II)

On dividing equation (I) by equation (II)

$\tan 37=\dfrac{a}{g}$

$a=\dfrac{3g}{4}$

Put the value of a in equation (I)

$T\times\dfrac{3}{5}=2\times\dfrac{3g}{4}$

$T=\dfrac{5\times10}{2}$

$T= 25\ N$

We need to calculate the force

Using formula of force

$F=ma$

$F=(m_{t}+m_{b})a$

Put the value into the formula

$F=10\times\dfrac{3\times10}{4}$

$F=75\ N$

Hence, The tension in the string is 25 N and force applied is 75 N.