A trolley, P, of mass 0.87 kg travelling at 0.56 ms-1 collides with a stationary trolley, R, of mass 0.78 kg. After the collision, both trolleys move in the same straight line. Trolley P travels at 0.22 ins-1 after(vskpkjfgdn) the collision. Calculate the speed of trolley R after the collision.
Answers
Answer:
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Explanation:
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Answer:
Mass of the trolley, M=200kg
Speed of the trolley, v=36km/h=10m/s
Mass of the boy, m=20kg
Initial momentum of the system of the boy and the trolley
=(M+m)v
=(200+20)×10
=2200kg m/s
Let v
′
be the final velocity of the trolley with respect to the ground.
Final velocity of the boy with respect to the ground =v
′
−4
Final momentum =Mv
′
+m(v
′
−4)
=200v
′
+20v
′
−80
From the conservation of linear momentum:
Initial momentum= Final momentum
2200=220v
′
−80
∴ v
′
=2280/220=10.36m/s
Length of the trolley, l=10m
Speed of the boy, v
′′
=4m/s
Time taken by the boy to run, t=10/4=2.5s
∴ Distance moved by the trolley =v
′′
×t= 10.36×2.5=25.9m
Explanation:
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