Question

A trolley rolls down an inclined plane with a

constant acceleration of 2 m/s2

. Find the distance

travelled between the instants when its velocities

are 10 m/s and 16 m/s.​

Answer 1

Answer:

A =6m/s^2

v = 30m/s 

u=25m/s

2as =v^2-u^2

2×6×s = 30^2 -25^2

12 s = 900 -625

d = 275 /12

22.3 is the distance

Answer 2

Answer:

u=10 m/s

v=16 m/s

a=2m/s^2

2aS=v^2-u^2

4S = 16^2 - 10^2

4S= 256-100= 156

156/4= 39