Question

A trolley while going down an incline plane has an acceleration of 2cm/s^2. what will be it's velocity 3s after start

Answer 1

Solution,

Here, we have

Initial velocity of the trolley, u = 0 (As starts from rest)

Acceleration of the trolley, a = 0.02 m/s²

Time taken by the trolley, t = 3 seconds

To Find,

Final velocity of the trolley, v = ?

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ v = 0 + 0.02 × 3

⇒ v = 0.02 × 3

⇒ v = 0.06 m/s

Hence, the final velocity of the trolley is 0.06 m/s.

Answer 2

Answer:

Initial velocity (u) = 0.06 m/s

Explanation:

Question-

A trolley, while going down an inclined plane, has an acceleration of 2cm/s². What will be its velocity 3s after the start?

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Given Information -

• Acceleration(retardation) =a= - 2cm/s² = - 0.02 m/s²
• Time(t) = 3 secs.
• Final velocity (v) = 0 m/s

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Required Solution-

• Initial velocity (u)

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Solution -

What to do?

$\rightarrow$ Equalising the units is the first step.

$\rightarrow$ Now, to find the initial velocity, we'll write the formula prior solving our answer. Then, we'll replace the values according to the given formula and solve it further.

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Formula(implemented in the case of given information) -

• $\underline{\boxed{\sf\purple{v = u+at}}}$

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Answer -

$\implies$ Replacing values while following the formula.

$0 = u + ( - 0.02 \times 3) \\ \\ 0 = u + ( - 0.06) \\ \\ 0= u - 0.06 \\ \\ 0.06 = u$

So, initial velocity is 0.06m/s.