Question

A trolley, while going down an inclined plane, has an acceleration of 2 cm//s^(2) starting from rest. What will be its velocity 3 s after the start ?

Answer 1

Explanation:

u= 0

a=2 cm/s^2

a=v-u/t

a=v-0/3

2×3=v

6cm/s =v

Answer 2

Solution,

Here, we have

Initial velocity of the trolley, u = 0 (As starts from rest)

Acceleration of the trolley, a = 0.02 m/s²

Time taken by the trolley, t = 3 seconds

To Find,

Final velocity of the trolley, v = ?

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ v = 0 + 0.02 × 3

⇒ v = 0.02 × 3

⇒ v = 0.06 m/s

Hence, the final velocity of the trolley is 0.06 m/s.