Math, asked by eeshadinesh2630, 7 months ago

A trolley while going down an inclined plane has an acceleration of 2 m/s2.what will be its velocity in 3 seconds after start?

Answers

Answered by loganrdmessi
13

Answer:

The velocity of the trolley after 3 seconds will be 6m/s

Step-by-step explanation:

Given:-

initial velocity = 0m/s

acceleration = 2m/s^2

time = 3s

Now,

By using first equation of motion, that is

v = u+at

v = 0+ 2*3

v = 6m/s

I hope it will help you

Answered by sangeetadas59023
2

Answer:

Given:

Given:a = 2cm/s² = 0.02m/s²

Given:a = 2cm/s² = 0.02m/s²u = 0m/s

Given:a = 2cm/s² = 0.02m/s²u = 0m/st = 3secs

Given:a = 2cm/s² = 0.02m/s²u = 0m/st = 3secsTo find:

Given:a = 2cm/s² = 0.02m/s²u = 0m/st = 3secsTo find:final velocity, v = ?

Given:a = 2cm/s² = 0.02m/s²u = 0m/st = 3secsTo find:final velocity, v = ?Solution:

Given:a = 2cm/s² = 0.02m/s²u = 0m/st = 3secsTo find:final velocity, v = ?Solution:v = u + at

Given:a = 2cm/s² = 0.02m/s²u = 0m/st = 3secsTo find:final velocity, v = ?Solution:v = u + atv = 0 + 0.02(3)

Given:a = 2cm/s² = 0.02m/s²u = 0m/st = 3secsTo find:final velocity, v = ?Solution:v = u + atv = 0 + 0.02(3)v = 0.06m/s

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